Recently I needed to use a thread pool for multithreading in an application. Sometimes logs and monitoring showed that an asynchronous task had suddenly stopped, leaving me bewildered and unable to investigate. A senior colleague eventually inspected the business code and found that a task in a new thread had thrown a runtime exception, causing the user thread I started to “fall over.” Why do threads in a thread pool not expose the exception? What state does a thread that throws an exception enter? This post analyzes that.

Reproducing the cases

#submit

  1. The task executed by the thread throws an exception, but it is not handled.
  2. The user thread with the business exception does not “die”; it becomes WATTING.
  3. The program continues to run.

#execute

  1. The task executed by the thread throws an exception, and it is successfully captured.
  2. The user thread with the business exception ends directly and becomes TERMINATED.
  3. The system does not end and continues running.

#schedule

  1. The task executed by the thread throws an exception, but it is not handled.
  2. The thread-pool thread is WATTING.
  3. The program continues running, but the periodic task that threw the exception no longer runs.

Cause analysis

#execute

For execute, this is easy to understand. The source code shows that when a thread-pool thread runs runWorker, if a task throws an exception, the thread throws it directly:

 final void runWorker(Worker w) {
     // ... 省略代码
     try {
         while (task != null || (task = getTask()) != null) {
             // ... 省略代码
             try {
                 beforeExecute(wt, task);
                 Throwable thrown = null;
                 try {
                     task.run();
                 } catch (RuntimeException x) {
                     thrown = x; throw x; // 这里抛出异常
                 } catch (Error x) {
                     thrown = x; throw x;
                 } catch (Throwable x) {
                     thrown = x; throw new Error(x);
                 } finally {
                     afterExecute(task, thrown);
                 }
             } finally {
                 task = null;
                 w.completedTasks++;
                 w.unlock();
             }
         }
         completedAbruptly = false;
     } finally {
         processWorkerExit(w, completedAbruptly); // 抛出异常后，执行这里
     }
 }

After an exception, to prevent the exceptional task from contaminating its thread, the worker that executed it is destroyed and a new non-core worker with no initial task is created. Therefore, even if every task in the pool fails, as long as the core-pool size is nonzero, the program remains blocked in workQueue#poll and the JVM does not exit.

private void processWorkerExit(Worker w, boolean completedAbruptly) {
    if (completedAbruptly) // If abrupt, then workerCount wasn't adjusted
        decrementWorkerCount();

    final ReentrantLock mainLock = this.mainLock;
    mainLock.lock();
    try {
        completedTaskCount += w.completedTasks;
        workers.remove(w); // 移除当前异常Worker
    } finally {
        mainLock.unlock();
    }

    tryTerminate();

    int c = ctl.get();
    if (runStateLessThan(c, STOP)) { // 如果不是STOP状态
        if (!completedAbruptly) {
            int min = allowCoreThreadTimeOut ? 0 : corePoolSize;
            if (min == 0 && ! workQueue.isEmpty())
                min = 1;
            if (workerCountOf(c) >= min) // 且线程数小于核心线程
                return; 
        }
        addWorker(null, false); // 新增一个线程执行
    }
}

#submit

submit is somewhat special because its task has a return value. When it is submitted, the pool wraps it in a FutureTask:

public Future<?> submit(Runnable task) {
    if (task == null) throw new NullPointerException();
    RunnableFuture<Void> ftask = newTaskFor(task, null); // 封装该应用
    execute(ftask);
    return ftask;
}

Thus, when the pool runs runWorker, it actually enters the following method:

public void run() {
    // ... 省略代码
    try {
        Callable<V> c = callable;
        if (c != null && state == NEW) {
            V result;
            boolean ran;
            try {
                result = c.call();
                ran = true;
            } catch (Throwable ex) {
                result = null;
                ran = false;
                setException(ex); // FutureTask会catch异常
            }
            if (ran)
                set(result);
        }
    } finally {
        // ... 省略代码
    }
}

The explanation now becomes clear: FutureTask wraps the exception as the outcome Object. When FuntureTask#get calls report, it wraps and rethrows the exception as ExecutionException:

public V get() throws InterruptedException, ExecutionException {
    int s = state;
    if (s <= COMPLETING)
        s = awaitDone(false, 0L);
    return report(s);
}
private V report(int s) throws ExecutionException {
    Object x = outcome;
    if (s == NORMAL)
        return (V)x;
    if (s >= CANCELLED)
        throw new CancellationException();
    throw new ExecutionException((Throwable)x); // 抛出该异常
}

The pool thread is WAITING because after this task ends, Worker is blocked while calling workQueue#poll.

#schedule

#schedule executes in a scheduled thread pool. In theory, a task should still run periodically after throwing an exception, so why does it stop? Look at ScheduledFutureTask, a subclass of FutureTask: normally, after a scheduled task runs, its thread puts it back into the execution queue.

public void run() {
    boolean periodic = isPeriodic();
    if (!canRunInCurrentRunState(periodic))
        cancel(false);
    else if (!periodic)
        ScheduledFutureTask.super.run();
    else if (ScheduledFutureTask.super.runAndReset()) { 
        setNextRunTime();
        reExecutePeriodic(outerTask);// 重新将任务放到队列中执行
    }
}

But in #runAndReset, an exception makes #runAndReset return false. The periodic task is then not requeued, so a scheduled task that throws an exception is not run again.

protected boolean runAndReset() {
    // ...省略代码
    boolean ran = false;
    int s = state;
    try {
        Callable<V> c = callable;
        if (c != null && s == NEW) {
            try {
                c.call(); // don't set result
                ran = true;
            } catch (Throwable ex) {
                setException(ex); // 抛出异常后，ran仍然是false
            }
        }
    } finally {
        // ...省略代码
    }
    return ran && s == NEW; // 此处返回false
}

Solutions

  1. Catch and handle exceptions inside tasks so they do not interfere with thread-pool execution.
  2. With #execute, use ThreadFactory to set logic for uncaught exceptions.
  3. With #submit or #schedule, which invoke through Callable, call #get to explicitly handle task exceptions.

Some thoughts

This problem is simple once thread pools are understood, but it exposed how insufficient my fundamentals were. I used to memorize interview material and could readily recite thread-pool ctl and every configuration; after some time, though, I was bewildered when actually using it and encountering a problem. As the saying goes: “What you have only read belongs to others; only what you have experienced is your own.”

How threads are shut down

When a thread pool shuts down, it closes some threads. How? On #shutdown, the pool traverses all workers and interrupts each idle thread. When an interrupted thread escapes the blocking #getTask, it checks two things again:

  1. Whether the queue is empty.
  2. Whether the current state is STOP (when shutDownNow is called).
private Runnable getTask() {
    boolean timedOut = false; // Did the last poll() time out?

    for (;;) {
        int c = ctl.get();
        int rs = runStateOf(c);

        // Check if queue empty only if necessary.
        if (rs >= SHUTDOWN && (rs >= STOP || workQueue.isEmpty())) {
            decrementWorkerCount();
            return null; // 如果是shutDown则退出
        }

        // ... 省略代码
    }
}

If these conditions apply, #getTask returns null. The worker enters #processWorkerExit and closes itself. Entering #addWorker then reveals two further conditions:

  1. STOP state.
  2. SHUTDOWN with an empty queue.
private boolean addWorker(Runnable firstTask, boolean core) {
    retry:
    for (;;) {
        int c = ctl.get();
        int rs = runStateOf(c);

        // Check if queue empty only if necessary.
        if (rs >= SHUTDOWN &&
            ! (rs == SHUTDOWN &&
               firstTask == null &&
               ! workQueue.isEmpty()))
            return false; // 此时便不会新增worker

    // ... 省略代码
    return workerStarted;
}

If they apply, no new thread is created.
Core idea: Interrupt idle threads to release them from **#poll** and close them. In SHUTDOWN state, they can close only after tasks finish; in STOP state, they close without waiting for tasks to finish.

Thread-pool knowledge

After reading ThreadPoolExecutor code, I took time to draw a diagram to deepen my understanding:

Likewise, as a subclass of ThreadPoolExecutor, ScheduledThreadPoolExecutor is broadly similar. Its biggest difference is the queue: the scheduled pool customizes DelayedWorkQueue. When a worker gets a task, the queue checks time and dequeues it only when the time is met. After a task runs, the scheduled pool requeues it for later invocation.